16c^2=35

Solution for 16c^2=35 equation:

16c^2=35

We move all terms to the left:

16c^2-(35)=0

a = 16; b = 0; c = -35;
Δ = b2-4ac
Δ = 02-4·16·(-35)
Δ = 2240
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2240}=\sqrt{64*35}=\sqrt{64}*\sqrt{35}=8\sqrt{35}$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{35}}{2*16}=\frac{0-8\sqrt{35}}{32}
=-\frac{8\sqrt{35}}{32}
=-\frac{\sqrt{35}}{4}
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{35}}{2*16}=\frac{0+8\sqrt{35}}{32}
=\frac{8\sqrt{35}}{32}
=\frac{\sqrt{35}}{4}
$